Practice: JavaScript Loops and Conditionals

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Free Online Course: Practice: JavaScript Loops and Conditionals provided by LinkedIn Learning is a comprehensive online course, which lasts for 1-2 hours worth of material. The course is taught in English and is free of charge. Upon completion of the course, you can receive an e-certificate from LinkedIn Learning. Practice: JavaScript Loops and Conditionals is taught by J. David Eisenberg.

Overview
  • Assess your JavaScript skills and practice techniques that fill the gaps.

Syllabus
  • Introduction

    • Assess and practice your JavaScript loops and conditionals
    • System setup
    1. Assess Yourself
    • Choose your adventure
    2. Working with Conditionals
    • If and else decision-making
    • Challenge: High-deposit alerts
    • Solution: High-deposit alerts
    • Challenge: Stay above zero
    • Solution: Stay above zero
    • Challenge: Calculate discount offerings
    • Solution: Calculate discount offerings
    • Challenge: Quadratic formula
    • Solution: Quadratic formula
    • Challenge: Putting it all together
    • Solution: Putting it all together
    • Switch
    • Challenge: Calculate days in a month
    • Solution: Calculate days in a month
    3. Working with Loops
    • While structure
    • Challenge: The Collatz conjecture
    • Solution: The Collatz conjecture
    • Challenge: Playing dice
    • Solution: Playing dice
    • Challenge: Calculate the break-even point of a loan
    • Solution: Calculate the break-even point of a loan
    • Challenge: Simulate an express lane checkout
    • Solution: Simulate an express lane checkout
    • For loops
    • Challenge: Calculate minimum and maximum sales
    • Solution: Calculate minimum and maximum sales
    • Challenge: Indexed for loops to convert binary to decimal
    • Solution: Indexed for loops to convert binary to decimal
    • Challenge: Use for-of to convert binary numbers to decimal
    • Solution: Use for-of to convert binary numbers to decimal
    • Challenge: Build an inverted triangle
    • Solution: Build an inverted triangle
    Conclusion
    • Next steps